Mathematically, this is 8x7x6x5x4, which equals 6,720. The first chair can be sat in by any of the 8 people.
How many ways can 8 people sit on 5 chairs?
you have a total of 8 chairs. 5 people can occupy these chairs in P(8,5) = 8! / 3! = 6720 ways.
How many ways can 7 people be seated in 5 chairs?
There are _7C5=7! 5! ⋅2! =21 ways of choosing which 5 chairs from the 7 will have people sitting in them.
How many ways can 8 adults be arranged in 8 chairs?
So I have 5! ⋅6⋅5⋅4=1440 ways to do that.
How many ways can all them be seated in a row of 8 chairs?
We need to multiply the permutation above by 2, since the two people insisting to sit next to each other has a choice if they are to be seated left or right of each other. Therefore, there are 10080 possible ways for eight people to be seated in a row of 8 chairs if two people insist on sitting next to each other.
How many ways can 5 people?
Answer: If the symmetry of the table is not taken into account the number of possibilities is 5! = 120. In this case it would be the same as ordering people on a line. However if rotation symmetry is taken into account, there are five ways for people to sit at the table which are just rotations of each other.
How many ways can 5 people sit in a theater?
Then there are 4 remaining possibilities for the second seat in the row, 3 remaining possibilities for the third seat, 2 remaining possibilities for the fourth seat, and the fifth seat has only 1 remaining possibility. The total number of possibilities is thus 5*4*3*2*1 = 5!, or 120.
How many ways can you arrange 5 different books on a shelf?
That’s 5! So, there are 120 ways to arrange five books on a bookshelf.
How many different ways can 7 students be seated in a row of 3 chairs *?
So there are 5040 ways of arranging seven people in a row of seven chairs.
How many distinct permutations can be formed using the letters of the word statistics?
If all of the ten (10) letters in the word “statistics” were different, this would be a simple permutation problem. The number of different arrangements of those letters would be simply 10! (10 factorial) = 3,628,800.
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How many ways can 7 people sit in a circular table with 7 seats?
Complete step-by-step answer: Since in this question we have to arrange persons in a circle and 7 persons have to be arranged in a circle so that every person shall not have the same neighbor. Hence there are 360 ways to do the above arrangement and therefore the correct option is A.
How many ways can 7 people be seated around a table?
If we are using chairs, then the number of combinations is (7−1)! as previously noted. However if we are using a circular bench, then the location of the first two sitters is irrelevant. Accordingly the next five sitters can be placed in (7−2)! =720 ways.
How many ways can 3 people sit in 3 chairs?
So there are two answers: There are 3! = 6 different ways of placing these three people in three distinct chairs. However, it we decide to consider rotated arrangements as basically the same, then there are only 2 ways.
How many ways can 8 people be in a line?
∴ There are 40,320 possible ways 8 students can be arranged in a line.
How many ways can 8 persons be seated at a round table?
So the answer is that there are 5,040 possible permutations of 8 people around a circular table.
How many ways can eight people be seated around a circular table if two of them insist on sitting beside each other?
=6! ways. Hence total no of ways 8 persons can be seated around a round table such that 2 given persons are seated next to each other = 2*6! = 1440.
How many ways can 5 sit in a car with 5 seats?
The number of arrangements possible for this case would be 3*4*3*2*1 = 72 possibilities. If, on the other hand, the car does not have to move, that means 5 choices for the driver seat, 4 choices for the 1st passenger seat, and so on, so therefore there are 5! or 120 possibilities for this case.
How many ways can 5 people a/b/c d and e sit in a row at a movie theater if C must sit to the right of but not necessarily next to B?
Since there are a total of 120 ways in which the five friends can sit in the five seats, and 8 of those ways in which B and C can sit together, that leaves 120–8 = 112 ways in which the friends can sit do that B and C do not sit together. So the answer is 112.
How many ways can five people sit in a row at a movie theater if order matters?
The answer is 120. There are 120 different ways these five people could sit in the four available seats at the movies.
How many ways can 5 things be arranged?
So we say that there are 5 factorial = 5! = 5x4x3x2x1 = 120 ways to arrange five objects.
How many ways can 5 people be seated in a row that has 5 chairs If 2 of the 5 people insist on sitting next to each other?
=1*2*3*4*5 =120 ways you can seat 5 people in a row of 5 chairs. So no. Of ways the can be seated=5×4×3×2×1=120. So, 5 people can be seated in 5 seats in 120 ways.
How many ways can you arrange seven students in a row?
1 = 7! = 5040$ ways of arranging 7 people in a row respectively.
How many ways can five persons be arranged in a row for picture taking if three of them insist on sitting next to one another?
= 5*4*3*2*1 = 120.
How many different ways can 8 books be arranged on a shelf?
8 books can be placed on a shelf in 8*7*6*5*4*3*2*1 ways. That equals to 40320.
How many ways can 5 different books be stacked on a shelf Brainly?
So since the books are all different, we are going to use permutation. nPr = n!/(n-r)! So for arranging 5 different books on a shelf, we have 5P5 ways. Hence we can arrange 5 different books in 120 different ways on a shelf.
How many ways can 7 books be arranged on a shelf 5 at a time?
7 books can be arranged on a shelf 5 at a time in 2520 ways.
How many ways can you line up a family of 5 for a picture?
5P5 = Arrangement of five different things = (5!)/(0!) = 120 ways.
How many ways can the letters in the word assessment be arranged?
The word ASSESS has 1A, 4S and 1E and above statement wants this word to be arranged so this is a problem from Permutations. 6!/4! = 30 ways.
How many different ways can the alphabet be arranged if the vowels must remain in the same place?
So, keeping the order of vowels unchanged, total number of possible arrangements = (6*60) = 360.
How many ways can 5 people sit around a circular table if Alice and Bob won't sit next to each other?
= 362,880 ways. The number of circular permutations of distinct objects is , because permutations related by a simple rotation are not considered different.
How many ways are there to seat 6 people at a round table with 6 chairs if you're only paying attention to who is sitting next to whom?
Example 1 In how many ways can 6 people be seated at a round table? Solution As discussed in the lesson, the number of ways will be (6 – 1)!, or 120. (i) A and B always sit together.
